How does Unix search for executable files?
Problem
When a file is executed, how does Unix search for it? If there are multiple executable files in PATH with the same name, which one is preferred? Is the current directory included in the search when a file is executed? Suppose there is a file with name in the current directory. Would that work if it is executed and is not part of the ?
Error Output
executable.sh
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1 Fix
Fix for: How does Unix search for executable files?
The $PATH is searched from beginning to end, with the first matching executable being run. So directories at the beginning of $PATH take precedence over those that come later. Executables in the current directory (.) are only executed if . is in $PATH (which it usually isn't). There is no implicit inclusion of the current directory in the search path.
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