How do I get the output and exit value of a subshell when using "bash -e"?
Problem
Consider the following code outer-scope.sh inner-scope.sh I'm trying to get to exit when a call to fails. Since invokes a sub-shell, this doesn't happen. How else do I get the output of a function while preserving the fact that the function may exit with a non-zero exit code?
Error Output
#!/bin/bash
set -e
source inner-scope.sh
echo $(inner)
echo "I thought I would've died :("Unverified for your environment
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1 Fix
Fix for: How do I get the output and exit value of a subshell when using "bash -e"?
preserves the exit status; you just have to use it in a statement that has no status of its own, such as an assignment. After this, would contain the exit status of , and you can use all sorts of checks for it: Or: Or: (Note: A bare without arguments is equivalent to – that is, it exits with the last command's exit status. I used the second form only for clarity.) Also, for the record: is completely unrelated in this case. You can just define in the file, with the same results.
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