Passing a powershell variable as output directory in 7zip

Fresh3 days ago

Mar 15, 20265743 views

Confidence Score0%

Problem

I need to execute something like inside a powershell script, but substitute destination folder (C:\Destination) with a variable. Some like: which obviously does not work. The previous statement in fact creates a folder with actual name How can this be done?

Error Output

7za e $file_path -oC:\Destination

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Fix for: Passing a powershell variable as output directory in 7zip

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I think this should work, but it doesn't for me for some reason: This will work: This will also work (it's just condensing the previous one into one line):

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Passing a powershell variable as output directory in 7zip

Problem

Error Output

1 Fix

Fix for: Passing a powershell variable as output directory in 7zip

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